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Let total work = 30 units (LCM of 10 and 15) Efficiency of ‘A’ = (30/10) = 3 units/day Efficiency of ‘B’ = (30/15) = 2 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (30/3) = 10 units/day Efficiency of ‘C’ = 10 – (3 + 2) = 5 units/day Required time taken = (30/5) = 6 days
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