A work can be completed by ‘A’ and ‘B’, alone in 10 days and 15 days, respectively. Find the number of days taken by ‘C’ to complete the same work alone if ‘A’, ‘B’ and ‘C’ together can complete the whole work in 3 days.
Let total work = 30 units (LCM of 10 and 15) Efficiency of ‘A’ = (30/10) = 3 units/day Efficiency of ‘B’ = (30/15) = 2 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (30/3) = 10 units/day Efficiency of ‘C’ = 10 – (3 + 2) = 5 units/day Required time taken = (30/5) = 6 days
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