A work can be completed by ‘A’ and ‘B’, alone in 18 days and 12 days, respectively. Find the number of days taken by ‘C’ to complete the same work alone if ‘A’, ‘B’ and ‘C’ together can complete the whole work in 4 days.
Let total work = 36 units (LCM of 18 and 12) Efficiency of ‘A’ = (36/18) = 2 units/day Efficiency of ‘B’ = (36/12) = 3 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (36/4) = 9 units/day Efficiency of ‘C’ = 9 – (2 + 3) = 4 units/day Required time taken = (36/4) = 9 days
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