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Let total work = 30 units (LCM of 15 and 10) Efficiency of ‘A’ = (30/15) = 2 units/day Efficiency of ‘B’ = (30/10) = 3 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (30/5) = 6 units/day Efficiency of ‘C’ = 6 – (2 + 3) = 1 units/day Required time taken = (30/1) = 30 days
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In the following question, a part of the sentence is underlined. Below the sentence are three alternatives to the underlined part. Select the alternativ...
