Question
A work can be completed by βAβ and βBβ, alone in
7 days and 14 days, respectively. Find the number of days taken by βCβ to complete the same work alone if βAβ, βBβ and βCβ together can complete the whole work in 4 days.Solution
Let total work = 14 units (LCM of 7 and 14) Efficiency of βAβ = (14/7) = 2 units/day Efficiency of βBβ = (14/14) = 1 units/day Combined efficiency of βAβ, βBβ and βCβ = (14/4) = 3.5 units/day Efficiency of βCβ = 3.5 β (2 + 1) = 0.5 units/day Required time taken = (14/0.5) = 28 days
Select the option in which figure is embedded.

Select the option in which the given figure X is embedded (rotation is not allowed).
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From the given answer figures, select the one in which the question figure is hidden / embedded(rotation is not allowed).
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From the given answer figure select the one in which the question figure is hidden/embedded in the same direction.