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Let the total work be 60 units. {LCM (10 and 12)} So, efficiency of ‘A’ = (60/10) = 6 units/day So, efficiency of ‘B’ = (6 x 0.5) = 3 unit/day Efficiency of ‘B’ and ‘C’ together = (60/12) = 5 units/day So, efficiency of ‘C’ = 5 – 3 = 2 units/day So, time taken by ‘C’ to finish the work alone = (60/2) = 30 days
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