Question
βAβ alone can do some work in 13 days. βBβ and
βCβ together can do the same work in 18 days. If βBβ is half as efficient as βAβ, then find the time taken by βCβ to complete the work alone.Solution
Let the total work be 234 units. {LCM (13 and 18)} So, efficiency of βAβ = (234/13) = 18 units/day So, efficiency of βBβ = (18 x 0.5) = 9 unit/day Efficiency of βBβ and βCβ together = (234/18) = 13 units/day So, efficiency of βCβ = 13 β 9 = 4 units/day So, time taken by βCβ to finish the work alone = (234/4) = 58.5 days
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