Question
‘A’ alone can do some work in 13 days. ‘B’ and
‘C’ together can do the same work in 18 days. If ‘B’ is half as efficient as ‘A’, then find the time taken by ‘C’ to complete the work alone.Solution
Let the total work be 234 units. {LCM (13 and 18)} So, efficiency of ‘A’ = (234/13) = 18 units/day So, efficiency of ‘B’ = (18 x 0.5) = 9 unit/day Efficiency of ‘B’ and ‘C’ together = (234/18) = 13 units/day So, efficiency of ‘C’ = 13 – 9 = 4 units/day So, time taken by ‘C’ to finish the work alone = (234/4) = 58.5 days
4Â Â Â Â Â 6Â Â Â Â Â Â 12Â Â Â Â Â 30 Â Â Â Â Â Â 90 Â Â Â Â Â Â Â 310
...2592 1300 656 331 169.5 88.75
...- Find the wrong number in the given number series.
6, 12, 24, 50, 96, 192 112, 130, 155, 196, 254, 342
126Â Â Â Â Â 130 Â Â Â Â Â 114 Â Â Â Â Â Â 150Â Â Â Â Â 82 Â Â Â Â Â 186 Â Â Â Â Â 42
...66, 115, 34, 155, 14, 211
Find the wrong number in the given number series.
- 342, - 218, - 96, 27, 150, 273
420, 380, 340, 300, 280, 220, 180
Find the wrong number, in the given number series,
1680, 840, 2520, 630, 3150, 475
Find the wrong number in given number series.
3910, 3879, 3786, 3631, 3414, 3235.
