The ratio of efficiencies of X and Y for doing a certain work is 5 ∶ 9. Working together, they can complete a work in 15 days. X alone will complete 66(2/3)% of the same work in?
ATQ LCM (14, 15) = 210 Let the total work be 210 units. Work done each day by X and Y together = 210/15 ⇒ 14 units Work done by X each day = 14 × 5/(5 + 9) = 5 units Now, time taken by X to complete 66(2/3)% of the same work ⇒ (210 × 200/3 %) ÷ 5 ⇒ (210 × 2/3) ÷ 5 = 28 days
Find the value of x.
√441 ÷ 21+ √400 = 1 × x
(560 ÷ 32) × (720 ÷ 48) = ?
[(√576 × √144) ÷ √1296]2 = ? ÷ 3
(3/7) x 868 + 25% of 240 = (? + 65)
The value of ((0.27)2-(0.13)2) / (0.27 + 0.13) is:
2197 1/3 + 30% of 1800 = ?× 343 1/3
Simplify the following expression:
((32)4 - 1)/33×31× (210+1)
(7/4×18/21)+ (51/7× 28/17) + (25/2 × 48/10) =?
2222 ÷ 22 + 992 ÷ 16 + 650 ÷ 25 = ?
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
