If 15 women or 18 men or 12 boys can do a piece of work in 18 days of 10 hours each, find how many boys assisted by 5 women and 6 men will finish the same work in 20 days of 6 hours each.
Given, 15 women = 18 men = 12 boys So 5 woman =4 boys & 6 men=4 boys Now by chain rule, M1D1H1 =M2D2H2 So 12boys×18×10 = (Tboys+5women+4man×20×6 12boys×18×10 = (T +4+4)boys ×20×6 18 = T+8 or T = 10 Hence, 10 boys more are required.
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