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Let the total work = 260 units Then, efficiency of ‘A’ = (260/65) = 4 units/hour Work completed by ‘A’ alone in 40 hours = 4 × 40 = 160 units Remaining work = 260 – 160 = 100 units So, efficiency of ‘B’ = 100/25 = 4 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 4 + 4 = 8 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (260/8) = 32.5 hours
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