Question
βAβ alone can complete a work in 20 hours. βAβ
started the work alone and left after working on it for 15 hours. If βBβ completed the rest of the work in 20 hours then find the time taken by βAβ and βBβ together to complete the whole work.Solution
Let the total work = 240 units Then, efficiency of βAβ = (240/20) = 12 units/hour Work completed by βAβ alone in 15 hours = 12 Γ 15 = 180 units Remaining work = 240 β 180 = 60 units So, efficiency of βBβ = 60/20 = 3 units/hour Therefore, combined efficiency of βAβ and βBβ = 3 + 12 = 15 units/hour So, time taken by βAβ and βBβ together to complete the work = (240/15) = 16 hours
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