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Let the total work = 300 units Then, efficiency of ‘A’ = (300/40) = 7.5 units/hour Work completed by ‘A’ alone in 20 hours = 7.5 × 20 = 150 units Remaining work = 300 – 150 = 150 units So, efficiency of ‘B’ = 150/20 = 7.5 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 7.5 + 7.5 = 15 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (300/15) = 20 hours
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