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Let total amount of work be 20 units (LCM of 10 and 20). Efficiency of ‘A’ = 20/10 = 2 units/day Efficiency of ‘B’ = 20/20 = 1 units/day Amount of work done by ‘A’ and ‘B’ together in 3 days = (2 + 1) × 3 = 9 units Time taken by B to complete remaining work = {(20 – 9)/1} = 11 days
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