Question
‘A’ and ‘B’ can do a piece of work in 12 days
and 20 days, respectively. They started working together but ‘A’ left after 6 days. Find the time taken by ‘B’ to complete the remaining work.Solution
Let total amount of work be 60 units (LCM of 12 and 20). Efficiency of ‘A’ = 60/12 = 5 units/day Efficiency of ‘B’ = 60/20 = 3 units/day Amount of work done by ‘A’ and ‘B’ together in 6 days = (5 + 3) × 6 = 48 units Time taken by B to complete remaining work = {(60 – 48)/3} = 4 days
148, ‘?’ , 15 4 , 17 8 , 23 8 , 35 8 , 56 8
3601 3602 1803 604 154 36
...8, 7, 12, 35, 128, 635
14, 28, 54, 98, 154, 224
104Â Â Â Â Â 136Â Â Â Â Â 152Â Â Â Â 160Â Â Â Â Â 164Â Â Â Â Â ?
...A’ is the nth term of the given series and ‘B’ is the (n + 1)th term of the given
series. Choose the correct statement from the following s...
7    7       14    42   ?     840
...11Â Â Â 12.1Â Â Â Â 14.3Â Â Â Â 17.6Â Â Â Â Â 22Â Â Â Â Â ?
9Â Â Â 4.5Â Â Â 4.5Â Â Â 9Â Â Â 36Â Â Â ?
40 30 20 ? 7.5 4.375
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