Question
βAβ and βBβ can do a piece of work in 15 days
and 20 days, respectively. They started working together but βAβ left after 3 days. Find the time taken by βBβ to complete the remaining work.Solution
Let total amount of work be 60 units (LCM of 15 and 20). Efficiency of βAβ = 60/15 = 4 units/day Efficiency of βBβ = 60/20 = 3 units/day Amount of work done by βAβ and βBβ together in 3 days = (4 + 3) Γ 3 = 21 units Time taken by B to complete remaining work = {(60 β 21)/3} = 13 days
- What will come in place of (?), in the given expression.
(56 Γ 3) + (480 Γ· 6) = ? 4.5 times 5/0.9Γ 35% of 240 =?
(115 Γ 17 Γ 3)/(23 Γ 51) + ?3 = β169
If A = 0.84181818... then what will be the difference between the numerator and denominator of the lowest fraction form of A?
30% of 2200 +β?β x 50 β 1020 = 11x 306 +Β (β 2250 Γ· 0.1)Β Β
5 Γ 14 + 100 Γ· 4 = 62 + ?
β64 of β225 = β(25 + ?) X 12
{5% of (20 Γ 25) + 6% of (30 Γ35)} Γ· 11 = ?Β