Question
βAβ alone can complete a work in 12 days. βBβ
alone can complete the same work in 20 days. If βAβ and βBβ work together for 6 days, then the remaining work can be completed by βAβ alone in how many days?Solution
Let the total amount of work = 60 units {LCM of 12 and 20} Then, efficiency of βAβ = 60/12 = 5 units/day Efficiency of βBβ = 60/20 = 3 units/day Combined efficiency of βAβ and βBβ = 5 + 3 = 8 units/day Work completed by βAβ and βBβ together in 6 days = 6 Γ 8 = 48 units Remaining work = 60 β 48 = 12 units Time taken by βAβ alone to complete the remaining work = 12/5 = 2.4 days
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