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Let the total amount of work = 60 units {LCM of 15 and 20} Then, efficiency of ‘A’ = 60/15 = 4 units/day Efficiency of ‘B’ = 60/20 = 3 units/day Combined efficiency of ‘A’ and ‘B’ = 4 + 3 = 7 units/day Work completed by ‘A’ and ‘B’ together in 5 days = 5 × 7 = 35 units Remaining work = 60 – 35 = 25 units Time taken by ‘A’ alone to complete the remaining work = 25/4 = 6.25 days
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