Q can do a work in 15 days and R can do the two-third work done by P and Q together in a day. If R completes the work in 18 days, how many days will it take P to complete the work with R?
Q’s one day work = 1/15 R’s one day work =1/18 Given that R’s one day work = (2 )/3 × (P+Q) ∴ P+Q’s one day work = 1/18 × 3/2 = 1/12 ∴ P’s one day work = 1/12-1/15 = 1/60 Hence, P+R’s one day work = 1/60+1/18 = 13/180 ∴ No. of days taken by P and R to complete the work = 180/13 = 13 11/13 days
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