A can complete a work in 15 days. B takes 5 days less than A to complete the same work. In how many days can both of them together complete 60% of the work together?
Time taken by B to complete the work = 15 – 5 = 10 days Let the total work = 30 units Efficiency of A = 30/15 = 2 units/day Efficiency of B = 30/10 = 3 units/day Required time taken = 0.60 x 30/(2+3) = 3.6 days
(24.78 × 11.67) + (7199.67 ÷ 14.99) = ? × 12.65
(7008.79)2/7009.201 × √1442.76 × 0.4897 =?
29.98% of 549.99 = ? - 254.97 + 79.98% of 74.99
657.94 + 335.21 - 211.09 - 82.30 = ?
[(17.97)2 ÷ 47.67 X 11.67] ÷ 26.85 = ?2 - (10.98 X 65.98)
`11(2/13)` + `5(2/11)` - `3(4/9)` = ?
? = 540.24 + 1022.97 – 11.992
23.95% of 274.99 - 34.99% of 120.01 = 19.95% of ?
(23.99)2– (17.99)2+ (1378.88 + 44.88) ÷ ? = 607.998