A can complete a work in 15 days. B takes 5 days less than A to complete the same work. In how many days can both of them together complete 60% of the work together?
Time taken by B to complete the work = 15 – 5 = 10 days Let the total work = 30 units Efficiency of A = 30/15 = 2 units/day Efficiency of B = 30/10 = 3 units/day Required time taken = 0.60 x 30/(2+3) = 3.6 days
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