Question
A can complete a work in 18 days. B takes 6 days less
than A to complete the same work. In how many days can both of them together complete 50% of the work together?Solution
Time taken by B to complete the work = 18 – 6 = 12 days Let the total work = 36 units Efficiency of A = 36/18 = 2 units/day Efficiency of B = 36/12 = 3 units/day Required time taken = 0.50 x 36/(2+3) = 3.6 days
More Time and work Questions
116 ÷ 280 of 1/2 + 3/5 × 5/3 = ?
756 + 432 – 361 + ? = 990
What will come in place of the question mark (?) in the following expression?
(320 ÷ 8 + 22) × 4 = 60 + 40% of ?
(125 × 12 × √8100) ÷ 150 = ?
3? x 23 ÷ √ 256 = 40.5
Simplify the expression:
(4x² - 16) / (2x - 4)
Find the value of 5342.5 +543.45+54.345 +5.4345+0.54345.
65% of ? = 50 + 20 × 4
25% of 140 + 2 × 8 = ? + 9 × 5
18 + 28 ÷ 4 - 14 = ? - 35
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