A’ and ‘B’ together can complete a work in 10 days while ‘A’ takes 18 days to complete the same work alone. If ‘C’ is 25% more efficient than ‘B’, then find the time taken by ‘C’ alone to complete the whole work.
Let the total work = 90 units Efficiency of (A + B) = 90/10 = 9 units/day Efficiency of ‘A’ = 90/18 = 5 unit/day Therefore, efficiency of ‘B’ = 9 – 5 = 4 units/day Efficiency of ‘C’ = 1.25 × 4 = 5 units/day Required time taken = 90/5 = 18 days
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