A’ and ‘B’ together can complete a work in 25 days while ‘A’ takes 30 days to complete the same work alone. If ‘C’ is 20% more efficient than ‘B’, then find the time taken by ‘C’ alone to complete the whole work.
Let the total work = 150 units Efficiency of (A + B) = 150/25 = 6 units/day Efficiency of ‘A’ = 150/30 = 5 unit/day Therefore, efficiency of ‘B’ = 6 – 5 = 1 units/day Efficiency of ‘C’ = 1.2 × 1 = 1.20 units/day Required time taken = 150/1.20 = 125 days
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