A’ and ‘B’ together can complete a work in 10 days while ‘A’ takes 30 days to complete the same work alone. If ‘C’ is 50% more efficient than ‘B’, then find the time taken by ‘C’ alone to complete the whole work.
Let the total work = 30 units Efficiency of (A + B) = 30/10 = 3 units/day Efficiency of ‘A’ = 30/30 = 1 unit/day Therefore, efficiency of ‘B’ = 3 – 1 = 2 units/day Efficiency of ‘C’ = 1.5 × 2 = 3 units/day Required time taken = 30/3 = 10 days
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