P’s 5 days work is equal to Q’s 6 days work. If P and Q together can complete the work in 25 days then how much time Q will take to complete 60% of the work?
Ratio of efficiency of P and Q = 6:5 Let the efficiency of P and Q be 6x and 5x units per day respectively. Total work = 11x × 25 = 275x units Required time = (0.60 × 275x)/5x = 33 days
I. 12y2 + 11y – 15 = 0
II. 8x2 – 6x – 5 = 0
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. 6p² + 17p + 12 = 0
II. 12q² - 25q + 7 = 0
I. 5x² + 17x + 6 = 0
II. 2y² + 11y + 12 = 0
...I. 6x2 + 23x + 10 = 0
II. 2y2 - 3y - 5 = 0
I. 9/(4 )p + 7/8p = 21/12
II. 7/5p = 9/10q + 1/4
I. 49y2+ 35y + 6 = 0
II. 12x2+ 17 x + 6 = 0
I. 99 x² + 31 x – 110 = 0
II. 6y² - 31y + 35 = 0
I. 63x² + 146x + 80 = 0
II. 42y² + 109y + 70 = 0
I. 2x2 + 12x + 18 = 0
II. 3y2 + 13y + 12 = 0