(y+15) men can do a piece of work in (z-30) days. (y-15) men can do the same piece of work in (z+45) days. If (y+25) men can do the same work in (z-45) days, then find out the values of ‘y’ and ‘z’.
(y+15) men can do a piece of work in (z-30) days.
Total work = Men_1 x Days_1
= (y+15)x(z-30) Eq.(i)
(y-15) men can do the same piece of work in (z+45) days.
Total work = Men_2 x Days_2
= (y-15)x(z+45) Eq.(ii)
If (y+25) men can do the same work in (z-45) days.
Total work = Men_3 x Days_3
= (y+25)x(z-45) Eq.(iii)
So Eq.(i) = Eq.(ii).
(y+15)x(z-30) = (y-15)x(z+45)
yz-30y+15z-450 = yz+45y-15z-675
-30y+15z-450 = 45y-15z-675
45y-15z-675+30y-15z+450 = 0
75y-30z = 675-450
75y-30z = 225
5y-2z = 15 Eq.(iv)
So Eq.(i) = Eq.(iii).
(y+15)x(z-30) = (y+25)x(z-45)
yz-30y+15z-450 = yz-45y+25z-1125
-30y+15z-450 = -45y+25z-1125
45y-25z+1125-30y+15z-450 = 0
15y-10z+675 = 0
3y-2z = -135 Eq.(v)
So Eq.(iv)-Eq.(v).
5y-2z-(3y-2z) = 15-(-135)
5y-2z-3y+2z = 15+135
2y = 150
y = 75
Put the value of ‘y’ in Eq.(v)
3x75-2z = -135
225-2z = -135
225+135 = 2z
2z = 360
z = 180
So the values of ‘y’ and ‘z’ are 75 and 180 respectively.
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