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Let 'a', 'b' and 'c' is the working efficiency of A, B and C respectively. Let the total amount of work required = 90 units The time is taken by A and B to do a certain work = 45 days Therefore, The combined efficiency of A and B 90/ 45 = 2-unit a per day a + b = 2 The amount of work done by A and B in 10 days = 20 units the remaining work = 90-20 = 70 units The amount of work done A and B in the last 28 days [with C] = 56 units The amount of work done by C in 28 days = 70 - 56 = 14 units Therefore, The Efficiency of C =14/28 =1/2 Now, since the work done by C in 3 days is equal to the work done by B in 2 days, The amount of work done by C in 3 days = 3c units The amount of work done by C in 2 days = 2b units So, 3c =2b b =3c/2 =3/2×1/2 b=3/4. The efficiency of A =2-3/4 =5/4 Combined efficiency of A and C =1/2 +5/4 =7/4 The 70% of total work =90×70/100 =63. Taken time by A =63/ (7/4) = (63×4)/7 =252/7 =36days.
What will come in the place of question mark?
2, 5, 11, 23, ?
Select the number that will replace the question mark (?) in the following series.
35, 38, 43, 50, 61, 74, ?
Select the related number from the given alternatives.
29 : 65 : : 43 : ?
Select the missing number from the given alternatives:
Find the missing number by analysing the pattern followed by the numbers in each row.
Find the missing number by analysing the pattern followed by the numbers in each row.
What number should replace the question mark?
Insert the correct missing number from the choices given below: