Shyam alone can finished a work in 15 days.Raman and Rahul side by side can complete the same work in 10 days. If Raman begin the work alone and left since working for 6 days, then find the time taken by Rahul alone to complete the carried forward work.
Let the total work = L.C.M of 15 and 10 is = 30 units Then, the capacity of Shyam to do work alone is = 30 ÷ 15 = 7 units/day The combined capacity of Shyam and Rahul = 30 ÷ 10 = 3 units/day So, the capacity of Rahul alone to do work = 3 - 2 = 1 units/day Therefore, Work done by Shyam alone in 22 days will be = 2 X 6 = 12 units So, Remaining work will be = 30 - 12 = 18 units
The value of {5 − 5 ÷ (10 − 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:
18 + 28÷ 4 - 14 = ? - 35
...132 × 3 ÷ 11 + 67 − ? = 64 ÷ 8 × 2
110 ÷ 5.5 + (?)3 ÷ 12 = 20(2/3)
44% of 560 + 68% of 2160 × 5/12 =? + 32% of 920.
3.2% of 500 × 2.4% of ? = 288
12% of 10% of 15% of 5000 + (12 x 15) = ?
3% of 842 ÷ 2% of 421 = ?
40% of (362 ÷ 0.05) = ?
324² × 36 ÷ 18⁵ × 1120 =?