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Let the total work (LCM of 10, 20 and 30) = 60 units Efficiency of A = 60/10 = 6 units/day Efficiency of B = 60/20 = 3 units/day Efficiency of C = 60/30 = 2 units/day Work done by A and C together in 6 days = 6 × (6 + 2) = 48 units Remaining work = 60 – 48 = 12 units Efficiency of D = (12/3) – 3 = 1 unit/day Number of days taken by D to complete (1/5)th of the same work = (60/5)/1 = 12 days
Select an appropriate figure from the four options that will come in the place of question mark (?) and complete the figure.
Which figure should replace the question mark (?) if the series were to continue?
In each of the following questions, find out which of the answer figures can be formed from the pieces given in the problem figure.
Select an appropriate figure from the four options that would complete the figure.
