60 boys can complete a piece of work in 60 days. They started the work together. But at the end of every 10th day five more boys have joined. Exactly on which day will the whole work be completed?
ATQ, Required boys -hrs = 60 × 60 = 3600 boys-hrs. Boys-hrs completed in fifty(50) days = 10(60 + 65 + 70 + 75 + 80) = 3,500. Hence Balance left = 3600-3500 = 100 Let X days be required to complete the remaining 100 boys- hrs. Now, (x)(85) = 100 x = 1(3/17) days i.e., work is completed in 51(3/17) days i.e., on 52 nd day work is completed.
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