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ATQ, Given (1/w) + (1/(2w)) = (1/x) ((1/(w + 3)) + ((1/(2w - 10)) = (1/x) [(1/w) + (1/2w)] = [(1/(w+3)) + (1/(2w-10))] w = 45 Number of days they take to complete the work Ishan : 45 days, Bhanumati : 90 days, Rajat: 48 days and Govind: 80 days; [(1/45) + (1/90)] = (1/x) x = 30 Let us assume that Nirmal takes 'n' days to complete the work. [(1/(w - 5)) + (1/n)] = (1/x) = [(1/40) + (1/n)] = (1/30) n = 120; Mohit takes 40 days and Nirmal takes 120 days to complete the work. (I) 8×[(1/48) + (1/80)] is the part of the work completed by Rajat and Govind together in 8 days. (II) Nirmal alone can complete the work in 120 days. (III) In the fractions = (1/45), (1/90), (1/48), (1/80)........ (1/45) is the maximum. So Ishan is the most efficient. All three can be answered.
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