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ATQ, Given (1/w) + (1/(2w)) = (1/x) ((1/(w + 3)) + ((1/(2w - 10)) = (1/x) [(1/w) + (1/2w)] = [(1/(w+3)) + (1/(2w-10))] w = 45 Number of days they take to complete the work Ishan : 45 days, Bhanumati : 90 days, Rajat: 48 days and Govind: 80 days; [(1/45) + (1/90)] = (1/x) x = 30 Let us assume that Nirmal takes 'n' days to complete the work. [(1/(w - 5)) + (1/n)] = (1/x) = [(1/40) + (1/n)] = (1/30) n = 120; Mohit takes 40 days and Nirmal takes 120 days to complete the work. (I) 8×[(1/48) + (1/80)] is the part of the work completed by Rajat and Govind together in 8 days. (II) Nirmal alone can complete the work in 120 days. (III) In the fractions = (1/45), (1/90), (1/48), (1/80)........ (1/45) is the maximum. So Ishan is the most efficient. All three can be answered.
If '+' means '-', '-' means '+', '×' means '÷', and '÷' means '×', then the value of 42 – 12 × 3 + 8 ÷ 2 + ...
69,012 ___ 20,167 ___ 51,246 ___ 6 ___ 50,000 = 7,386
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`2/5` ___ 15 ___ 115___ 20 ___ 4 = 581
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If a dozen apples weigh 1.8 kg in total, how many apples will be there in 3 boxes weighing 23.250 kg each?
Solve : (3.2 × 104) ÷ (2 × 105)
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In an election two candidates participates. 20% voters did not vote. 25 % votes declared invalid and the winner get 80 % of the valid votes. If he win b...