Question
Working individually, 'A' can finish 60% of a task in 18
days, and 'B' takes 15 days longer than 'A' to complete the entire task. However, 'B' and 'C' working together can complete the task in 20 days. Now, What will be the amount of time 'C' would need to complete the same task when working alone.Solution
ATQ, Time taken by 'A' alone to complete the entire work = 18 ÷ 0.6 = 30 days Time taken by 'B' alone to complete the entire work = 30 + 15 = 45 days Let the total work = L.C.M of 30, 45 and 20 = 180 units Then, efficiency of 'B' = (180/45) = 4 units/day Combined efficiency of 'B' and 'C' = (180/20) = 9 units/day So, efficiency of 'C' alone = 9 - 4 = 5 units/day So, time taken by 'C' alone to complete the entire work = (180/5) = 36 days
A square prism has a base side of 10 cm and a height of 15 cm. If a cone with the same base and height is removed from the prism, what is the volume of ...
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If the sales of Product C increase by 50% and the sales of Product D decrease by 20%, what will be the new total sales of all products combined?
I). 3p 2  – 13p + 12 = 0
II). 4q 2 + 3q – 7 = 0
Anuj invested a certain amount for 18 months at a simple interest rate of 5% per annum and received a total of Rs. 3,440. What wo...
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The ratio of the ages of A and B is 3:4. Five years later, the ratio of their ages will be 4:5. What are their present ages?
Solve: 2(x+3) = 8(x–1)
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