ATQ, Let total amount of work be 525 units Amount of work done by ‘A’ in one day (with increased efficiency) = 525/25 = 21units Original efficiency of ‘A’ = 21/1.40 = 15 units per day Amount of work done by ‘B’ in one day (with increased efficiency) = 525/21 = 25units Original efficiency of ‘B’ = 25/1.25 = 20 units per day Amount of work completed by ‘A’ and ‘B’ together in 9 days = 35 × 9 = 315 units Remaining work = 525 – 315 = 210 units Desired time = 210/15 = 14 day
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