ATQ, Let the total work be 600 units. {LCM (40, 60 and 100)} So, efficiency of 'Alex' = 600 ÷ 40 = 15 units/day And efficiency of 'Ben' = 600 ÷ 60 = 10 units/day And efficiency of 'Charlie' = 600 ÷ 100 = 6 units/day So, work done in every 2 days = (15 × 2) + 10 + 6 = 46 units/day So, work done in 26 days = (26/2) × 46 = 598 units And time taken by 'Alex' and 'Ben' together to finish the remaining work on last day = {(600-598)/(15+10)} So, total time taken = 26 + (2/25) =26(2/5)
Statements: A $ B, B * C, D % A
Conclusions: a) C # D b) D $ B
Statements: P % Q, P $ R, Q # S, R @ T
Conclusions:
I. R $ Q
II. S & T ...
Statements: V ≤ R ≥ Q; R ≤ N < Y; I > Y ≤ S
Conclusions:
I. V ≤ S
II. I > Q
III. S > N
Statements: P < Q = S ≥ U; V ≤ P ≥ N > I
Conclusions: I. U < V II. Q > I
...Statements: N $ Q, Q @ M, M % S, S % T
Conclusions : I. S # Q II. S & Q III. M & T
...Statement: F > E = L ≤ V ≤ P = C
Conclusions:
I. C > E
II. E = C
III. F > P
IV. C ≥ E
...Statements: P ≥ U ≥ Y > T ≤ Q = V > R > S < W
Conclusion
I: Q > S
II: T ≤ P
Which of the following letters should be placed in the blank spaces respectively (in the same order from left to right) to complete the given expression...
Statement:T>U<V<X=C>S ;U<P ≥X
I.T < P
II. P > S
Statement: E ≤ F; E ≤ H; F = P; H < S
Conclusion:
I. S ≤ F
II. P ≥ S