Suppose Y individuals can complete a task in (Y - 28) days, and (Y + 12) individuals can finish the same task in (Y - 32) days, what is the number of days it would take for (3/4) Y individuals to complete the same task together?
we can say that let efficiency of a man be 'e' units/day ATQ, Y × (Y - 28) × e = (Y + 12) × (Y - 32) × e Y = 48 Hence total work will be = 48 × (48 - 28) × e = 960e units Required days will be then = 960e/(48 × (3/4) × e) = (80/3) or = 26(2/3) days
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