ATQ, Let the efficiency of a man and a women be 'a' and 'b' units/day respectively Then, [(32a + 28b) × 60]/1 = [(40a + 28b) × 40]/(4/5) 192a + 168b = 200a + 140b (a/b) = (7/2) Total work = [((32 × 7) + (28 × 2)) × 60] = 16800 units hence required days = [(2 × 16800) /(84×2)] = 200 days
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