Total work = 120 units (LCM of 30 and 40) Efficiency of ‘A’ = 120/30 = 4 units/day Efficiency of ‘B’ = 120/40 = 3 units/day According to the question, ‘A’ worked for ‘x’ days and ‘B’ worked for ‘2x days. Therefore, (4+3)x + 3 × 2x = 120 Or 7x + 6x = 120 Or x = 120/13 total time taken to complete the whole work = 3×120/13 =360/13 days =27.69days
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