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Total work = 120 units (LCM of 30 and 40) Efficiency of ‘A’ = 120/30 = 4 units/day Efficiency of ‘B’ = 120/40 = 3 units/day According to the question, ‘A’ worked for ‘x’ days and ‘B’ worked for ‘2x days. Therefore, (4+3)x + 3 × 2x = 120 Or 7x + 6x = 120 Or x = 120/13 total time taken to complete the whole work = 3×120/13 =360/13 days =27.69days
(225 + 125) ÷ 7 + 250 = ? + 20% of 800
(2/?) x (3/16) x (2/15) x 60 = 1/3
0.25% of 22200 – 18.3 = ?
Simplify the following expression:
36% of 250 + 26 ÷ 2 × ? = 207
6269 + 0.25× 444 + 0.8× 200 = ? × 15
...18(1/3) + 9(2/3) – 10(1/3) = 1(2/3) + ?
[(4/3) + (5/6)] of 378 = ?
√529 + √64 + 92 = ?