ATQ, Let the total amount of the work = LCM of 40 and 56 = 280 units Amount of the work done by Anita in one day = 280/40 = 7 units Amount of the work done by Binita in one day = 280/56 = 5 units Amount of the work done by Anita in 25 days = 25 × 7 = 175 units Rest amount of the work = 280 – 175 = 105 units Time taken by Binita to complete the work = 105/5 = 21 days
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What was the sum of the ages of the father and the daughter 5 years earlier?
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