Anita and Binita have individual completion times for a task; Anita can complete it in 40 days, while Binita can do it in 56 days. Anita initiated the task and worked for the first 25 days, after which Binita took over and finished the remaining work independently. What is the duration it took Binita to complete the remaining work?
ATQ, Let the total amount of the work = LCM of 40 and 56 = 280 units Amount of the work done by Anita in one day = 280/40 = 7 units Amount of the work done by Binita in one day = 280/56 = 5 units Amount of the work done by Anita in 25 days = 25 × 7 = 175 units Rest amount of the work = 280 – 175 = 105 units Time taken by Binita to complete the work = 105/5 = 21 days
Statement: P ≤ W < O = D ≥ G > T
Conclusions:
I. P ≤ T
II. W < D
Statements: T > U, V > W, U = X, R ≥ X, V = R
Conclusion:
I. T ≥ W
II. W > T
Which of the following expressions will be true if the expression P > Q = R < S = T ≤ U = V is definitely true?
In each of the questions below are given some statements followed by two conclusions. You have to take the given statements to be true even if they see...
Statements: J > O > B < N = T ≥ S < C < I ≤ P
Conclusion
I: P > B
II: N > S
Statement:G≥ K, K ≤ S, S = M, M < N
Conclusion: I. N > K II. G < S
Statement: X < V ≥ A > Y; A ≤ S < W
Conclusions:
I. X < W
II. S > Y
Statements: L ≥ O = J ≥ I ≤ V; C = T ≤ J
Conclusion: I. C < L II. C = L
Statements:
J ≥ F = P; F > S ≥ A; S ≥ B < C
Conclusions:
I. C > A
II. B < J
Statement:
R ≤ P >K ≤ L; W ≤ X = K > O; Q > L
Conclusion:
I) W < L
II) L = W
