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ATQ, Let the efficiency of M be ‘20m’ units/day For i: Efficiency of N = 20m × 0.75 = ‘15m’ units/day Total amount of work = (20m + 15m) × 15 = ‘525m’ units Time taken by N alone to complete the whole work = 525m ÷ 15m = 35 days Therefore, (i) is true. For ii: Efficiency of N = 20m × 0.50 = ‘10m’ units/day Total amount of work = (20m + 10m) × 15 = ‘450m’ units Time taken by N alone to complete the whole work = 450m ÷ 10m = 45 days Therefore, (ii) is true. For iii: Efficiency of N = 20m × 0.60 = ‘12m’ units/day Total amount of work = (20m + 12m) × 15 = ‘480m’ units Time taken by N alone to complete the whole work = 480m ÷ 12m = 40 days Therefore, (iii) is true.
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