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    Question

    A and B working together completed a job in 40/9 days.

    If A had worked twice as efficiently as she did and B had worked 1/3 of his actual efficiency, then the work would have been completed in 60 /17 days. Find the time A would take to complete the work alone.
    A 9days Correct Answer Incorrect Answer
    B 8days Correct Answer Incorrect Answer
    C 7days Correct Answer Incorrect Answer
    D 10days Correct Answer Incorrect Answer

    Solution

    20A=25B A/B=25/20 A/B=5/4 A: B=5:4 ATQ- Total work= (40/9) ×9 =40 Total work completed by A = 40/5=8 days

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