A, B, and C can finish work in 5 days, 10 days, and 15 days, respectively, working alone. A and B work on the first day, A and C work on the second day, A and B work on the third day, and so on till the work is completed. In how many days the work will be completed?
Working fashion=(A+B) + (A+C) +(A+B) …. Working in 2days = (6+3+6+2) =17 3days =17+9=26unit Remaining work =30-26=4unit Remaining work 4units is done by (A+C) 4days =4/8=1/2 days Total days= 3+1/2=7/2days .
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