P is 60% more efficient than Q. P takes 30 more days to finish a work as compared to the number of days taken by P and Q together to finish the same work. Find the time taken by Q to finish the same work alone.
Let efficiency of P = p and efficiency of Q = q p = 160% of q => p: q = 8: 5 Let time required by P and Q together to finish this job be “t”. (p + q) ×t = W => 13x × t = W …. (1) ATQ- p × (t + 30) = W => 8x × (t + 30) = W … (2) By solving above two equations we get t = 48 13x × 48 = 5x × T => T = 124.8 days
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