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ATQ, S alone can do the work in 16/0.4 = 40 days Let, total work be LCM of 36 and 40 = 360 units Units of work done by R in a day = 360/36 = 10 Units of work done by S in a day = 360/40 = 9 Units of work done by S on 10 days = 9 × 10 = 90 Remaining work = 360 – 90 = 270 units Let, M can do ‘m’ units work per day So, 270/(10 + m) = 12 270 = 120 + 12m 12m = 150 m = 12.5 Required time taken = 360/(9 + 12.5) = 720/43 days
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