ATQ, Let, the total work be 792 units (LCM of 88, 66 and 72) Amount of work done by 'B' and 'N' together in one day = (792/88) = 9 units Amount of work done by 'N' and 'S' together in one day = (792/66) = 12 units Amount of work done by 'B' and 'S' together in one day = (792/72) = 11 units Amount of work done by 'B', 'N' and 'S' together in one day = {(9 + 12 + 11) /2} = 16 units Amount of work done by 'B' alone in one day = 16 - 12 = 4 units Amount of work done by 'N' alone in one day = 16 - 11 = 5 units Amount of work done by 'S' alone in one day = 16 - 9 = 7 units So, the desired ratio = 4:5:7
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