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ATQ, Let, the total work be 792 units (LCM of 88, 66 and 72) Amount of work done by 'B' and 'N' together in one day = (792/88) = 9 units Amount of work done by 'N' and 'S' together in one day = (792/66) = 12 units Amount of work done by 'B' and 'S' together in one day = (792/72) = 11 units Amount of work done by 'B', 'N' and 'S' together in one day = {(9 + 12 + 11) /2} = 16 units Amount of work done by 'B' alone in one day = 16 - 12 = 4 units Amount of work done by 'N' alone in one day = 16 - 11 = 5 units Amount of work done by 'S' alone in one day = 16 - 9 = 7 units So, the desired ratio = 4:5:7
I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0
I. 35x² - 24x – 35 = 0
II. 72y² - 145y + 72 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
If x2 - 3x - 18 = 0 and y2 + 9y + 18 = 0, which of the following is true?
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 29x² - 177x + 270 = 0
Equation 2: 31y² - 152y + ...
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
I. 2x² + 11 x + 15 = 0
II. 2y² - 19 y + 44 = 0
I. 3x2 - 14x + 15 = 0
II. 15y2- 34 y + 15 = 0
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
I. 3p2 - 11p + 10 = 0
II. 42q2 + q -1 = 0