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ATQ, Let the total number of task achieved be ‘a’ and each Task are of 300b units of work. Efficiency of a 'A'= 300b/15 = 20b units/day Efficiency of a 'B' = 300b/25 = 12b units/day Efficiency of a 'C' = (1/2) × 20b = 10b units/day Now, total task achieved = a × 300b units Work done by 2A, 3B and 4C working together in 30days = 30 × (2 × 20b + 3 × 12b + 4 × 10b) units = 30 × (40b + 36b + 40b) units = 3480b units ATQ, a × 300b = 3480b Or, a = 3480/300 = 11.6
If A = (7)1/3 + (7) -1/3, then the value of {3A3 – 9A} will be:
√4096 + √(?) + 13 – 29 = 148
if a2 + b2 + c2 = 2(4a -5b -9c)-122 , then a-b-c = ?
If, 4x2 + y2 + 12x + 6y + 18 = 0, then find the value of (2x + y)/(y + 6x).
If a + b = 56 and (a – b)² = 496, find the value of the product of a and b.
The speed of a car is 25% more than that of a bike. Both of them start from a same point. After travelling for 4 hours, the speed of the bike is increas...
√(92×8 ×52+700) = ?