2 men and 3 boys can do a piece of work in 405 days while 3 men and 2 boys can do the same work in 324 days. In how many days can 5 men and 5 boys do that work?
According to the question, (2M+3B) x405 = (3M + 2B) ×324 810M+1215B=972M+648B 972M-810M=1215B-648B 162M = 567B M = 567B /162=7B / 2 Let 5 men and 2 boys complete the work in (x) days. (5M+5B) x = (3M + 2B) ×324 (5x7B/2+5B) x = (3x7B/2+2B) x324 (35B+10B) ×x/2=(25B×324)/2 (45B×x)/2 =25B×324)/2 X=(324×25B)/45B X=180days.
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