Question
A can do a job alone in 66 days, B can do it alone in 55
days, while A, B, and C working together can complete the job in 11 days. In how many days can C do the job alone?Solution
LCM (66, 55, 11) = 330 Let the total work be the individual time taken by the workers. Now, total work = 330 units Efficiencies, A does each day = 330/66 = 5 units B does each day = 330/55 = 6 units (A + B + C) together do each day = 330/11 = 30 units Now, C does each day = 30-(5+ 6) = 19 units Time taken by C to complete the job alone. = 330/19 17.3 days  In 17.3 days, C can do the job alone
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