Question
βGβ and βHβ can complete an assignment in 60
days, while βHβ and βIβ can complete it in 45 days. βGβ and βHβ worked together on it for 50 days, after which βIβ alone finished the remaining work in 12 days. If βGβ, βHβ, and βIβ commenced an assignment and worked jointly till completion, earning a total of Rs. 1650 in wages, then the share of βGβ will be:Solution
Total work = LCM of 60 and 45 = 180 units Work done by βGβ and βHβ per day = 180/60 = 3 units Work done by βHβ and βIβ per day = 180/45 = 4 units Work done by βGβ and βHβ in 50 days = 50 Γ 3 = 150 units Remaining work = 180 - 150 = 30 units Efficiency of βIβ = 30/12 = 2.5 units per day Efficiency of βHβ = 4 - 2.5 = 1.5 units per day Efficiency of βGβ = 3 - 1.5 = 1.5 units per day Share of βGβ = (1.5 / (1.5 + 1.5 + 2.5)) Γ 1650 = Rs 450 Β
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