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Let the total amount of work = 120 units (LCM of 40 and 30) Work done by ‘P’ and ‘Q’ together in one day = 120 / 40 = 3 units Work done by ‘Q’ and ‘R’ together in one day = 120 / 30 = 4 units Work done by ‘P’ and ‘Q’ together in 35 days = 35 × 3 = 105 units Remaining work = 120 - 105 = 15 units Efficiency of ‘R’ = 15 / 5 = 3 units per day Efficiency of ‘Q’ = 4 - 3 = 1 unit per day Efficiency of ‘P’ = 3 – 1 = 2 units per day Share of ‘P’ = (2 / (2 + 1 + 3)) × 1000 = 2/6 × 1200 = Rs 400
I. 63x² + 37 x – 40 = 0
II. 15 y² + 29 y + 12 = 0
I. 15y2+ 4y – 4 = 0
II. 15x2+ x – 6 = 0
I. 2x² - 15x + 13 = 0
II. 3y² - 6y + 3 = 0
Equation 1: x² - 220x + 12100 = 0
Equation 2: y² - 210y + 11025 = 0
l). p² - 29p + 204 = 0
ll). q² + 4q - 221 = 0
Equation 1: x² - 144x + 5184 = 0
Equation 2: y² - 130y + 4225 = 0
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
I. 2y² - 11 y + 15 = 0
II. 2x² + 3x – 14 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...