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    Question

    Before 'A' joined the team, 'S' and 'V' were alternating

    days to complete a project. In the final four days, 'A', 'S', and 'V' all worked together to finish the job. 'V' is 50% more efficient than 'S' and 20% more efficient than 'A'. If 'A' can complete the work by himself in 24 days and 'S' and 'V' worked for an equal number of days, calculate the total number of days it took to complete the work.
    A 25 days Correct Answer Incorrect Answer
    B 16 days Correct Answer Incorrect Answer
    C 22 days Correct Answer Incorrect Answer
    D 10 days Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Time taken by 'V' alone to do the work = 24/1.2 = 20 days Time taken by 'S' alone to do the work = 1.5 × 20 = 30 days Let, total work be LCM of 20, 30, and 24 = 120 units Units of work done by 'A', 'V', and 'S' in a day are 5 units, 6 units, and 4 units, respectively. So, units of work done in last 4 days = 15 × 4 = 60 units Remaining 60 units of work done in (60/10) × 2 = 12 days So total number of days = 12 + 4 = 16 days

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