ATQ, Total work = LCM of 24 and 40 = 120 units Efficiency of Mike = 120 / 24 = 5 units/day Efficiency of Jenny = 120 / 40 = 3 units/day Combined efficiency = 5 + 3 = 8 units/day Original time (d) = 120 / 8 = 15 days Required time (d/2) = 7.5 days Required total efficiency = 120 / 7.5 = 16 units/day Increase needed for Jenny = 16 - 5 = 11 units/day Percentage increase = ((11 - 3) / 3) × 100 = 266.67% or 267%
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