A can complete a piece of work in 27 days. He worked for 21 days and then B finished the remaining work in 8 days. In how many days can A and B finish the work together?
A can complete a piece of work in 27 days. A does the work in 27 days =1 A does the work in 1 day =1/27 A does the work in 21 days = (1/27) ×21=7/9 Remaining work =1-7/9 =2/9 Remaining work finished by B in 8 days =8×9/2=36days. A and B together finish the work – 27 36 108 4 3 =108/4+3 =108/7 =15(3/7) days.
456 x 99.999 + 654 = ?
10.992 + (5.01 × 7.98) + ? = 361.03
(14.66)2 + (343.84 ÷ 3.88 - 55.87) = ? + 91.23
49.97% of 2016 – 37.99% of 1050 = ? – 47.98% of 5950
? = 44.78% of 839.91 – 48.12% of 774.89 + 55.77% of 1024.85
3.55% of 8120 – 66.66% of 540 = ? – 28% of 5500
? = 540.24 + 1022.97 – 11.992
9.95% of 1299.99 + 19.95 × 17.05 - 299.99 = ?
